2021-09-17 Sparsity, solvers, and nonlinear intro¶
Last time¶
Advection and boundary layers
The (cell) Péclet number and oscillations
Today¶
Effective use of sparse/structured matrices
Intro to rootfinding and Newton’s method
using Plots
using LinearAlgebra
function vander(x, k=nothing)
if k === nothing
k = length(x)
end
V = ones(length(x), k)
for j = 2:k
V[:, j] = V[:, j-1] .* x
end
V
end
function fdstencil(source, target, k)
"kth derivative stencil from source to target"
x = source .- target
V = vander(x)
rhs = zero(x)'
rhs[k+1] = factorial(k)
rhs / V
end
fdstencil (generic function with 1 method)
Advection-diffusion with conservative FD¶
\[(- \kappa u_x + wu)_x = f\]
function advdiff_conservative(n, kappa, wind, forcing)
x = LinRange(-1, 1, n)
xstag = (x[1:end-1] + x[2:end]) / 2
L = zeros(n, n)
rhs = forcing.(x)
kappa_stag = kappa.(xstag)
for i in 2:n-1
flux_L = -kappa_stag[i-1] * fdstencil(x[i-1:i], xstag[i-1], 1) + wind * [.5 .5]
flux_R = -kappa_stag[i] * fdstencil(x[i:i+1], xstag[i], 1) + wind * [.5 .5]
weights = fdstencil(xstag[i-1:i], x[i], 1)
L[i, i-1:i+1] = weights[1] * [flux_L..., 0] + weights[2] * [0, flux_R...]
end
L[1, 1] = 1
rhs[1] = 0
L[2:end, 1] .= 0
L[end,end] = 1
rhs[end] = 0
L[1:end-1,end] .= 0
x, L, rhs
end
advdiff_conservative (generic function with 1 method)
Experiments, The Péclet number¶
(11)¶\[\begin{align}
(- \kappa u_x + wu)_x &= f & \mathrm{Pe}_h &= \frac{h \lvert w \rvert}{\kappa}
\end{align}\]
n = 40; h = 2/n
kappa = 1
wind = 100
x, L, rhs = advdiff_conservative(n, x -> kappa, wind, one)
@show minimum(diff(x))
plot(x, L \ rhs, marker=:auto, legend=:none, title="Pe_h $(wind*h/kappa)")
minimum(diff(x)) = 0.0512820512820511
Upwinded discretization¶
Idea: incoming advective flux should depend only on upwind value, outgoing should depend only on my value.
function advdiff_upwind(n, kappa, wind, forcing)
x = LinRange(-1, 1, n)
xstag = (x[1:end-1] + x[2:end]) / 2
L = zeros(n, n)
rhs = forcing.(x)
kappa_stag = kappa.(xstag)
for i in 2:n-1
flux_L = -kappa_stag[i-1] * fdstencil(x[i-1:i], xstag[i-1], 1) +
wind * (wind > 0 ? [.75 .25] : [0 1]) # <--- was [.5 .5]
flux_R = -kappa_stag[i] * fdstencil(x[i:i+1], xstag[i], 1) +
wind * (wind > 0 ? [.75 .25] : [0 1]) # <--- was [.5 .5]
weights = fdstencil(xstag[i-1:i], x[i], 1)
L[i, i-1:i+1] = weights[1] * [flux_L..., 0] + weights[2] * [0, flux_R...]
end
L[1, 1] = 1
rhs[1] = 0
L[2:end, 1] .= 0
L[end,end] = 1
rhs[end] = 0
L[1:end-1,end] .= 0
x, L, rhs
end
advdiff_upwind (generic function with 1 method)
Try it for robustness¶
n = 40; h = 2/n
kappa = 1
wind = 1000
x, L, rhs = advdiff_upwind(n, x -> kappa, wind, one)
@show minimum(diff(x))
plot(x, L \ rhs, marker=:auto, legend=:none, title="Pe_h $(wind*h/kappa)")
minimum(diff(x)) = 0.0512820512820511
What is the order of accuracy of this upwind discretization?¶
How expensive is \
?¶
x, L, rhs = advdiff_upwind(5000, x -> kappa, wind, one)
@timev L \ rhs;
1.670357 seconds (6 allocations: 190.792 MiB)
elapsed time (ns): 1670356501
bytes allocated: 200060272
pool allocs: 3
malloc() calls: 3
function elapsed_solve(n)
x, L, rhs = advdiff_upwind(n, x -> kappa, wind, one)
@elapsed L \ rhs
end
ns = (1:6) * 1000
times = elapsed_solve.(ns)
6-element Vector{Float64}:
0.012454447
0.083467243
0.334782038
0.534024244
1.20161831
1.406723185
scatter(ns, times, xscale=:log10, yscale=:log10)
plot!(ns, [(ns/3000).^2, (ns/3000).^3], xrange=(1e3, 1e4))
How long would \(n=10000\) take to solve?¶
How much memory would \(n=10000\) take?¶
Sparsity¶
x, L, rhs = advdiff_upwind(20, one, 1, one)
spy(L, marker=(:square, 10), c=:bwr)
using SparseArrays
sparse(L)
20×20 SparseMatrixCSC{Float64, Int64} with 54 stored entries:
⠱⣦⡀⠀⠀⠀⠀⠀⠀⠀
⠀⠈⠻⣦⡀⠀⠀⠀⠀⠀
⠀⠀⠀⠈⠻⣦⡀⠀⠀⠀
⠀⠀⠀⠀⠀⠈⠻⣦⡀⠀
⠀⠀⠀⠀⠀⠀⠀⠈⠻⢆
How does solving with the sparse matrix scale?¶
function elapsed_solve(n)
x, L, rhs = advdiff_upwind(n, x -> kappa, wind, one)
L = sparse(L)
@elapsed L \ x
end
ns = (1:10) * 1000
times = elapsed_solve.(ns)
scatter(ns, times, xscale=:log10, yscale=:log10)
plot!([n -> 1e-2*n/1000, n -> 1e-2*(n/1000)^2, n -> 1e-2*(n/1000)^3])
How much memory is needed?¶
SparseArrays Compressed Sparse Column (CSC)¶
# starting with a dense matrix
A = sparse([1 0 0 -2; 0 3.14 0 .4; 5.1 0 0 .06])
3×4 SparseMatrixCSC{Float64, Int64} with 6 stored entries:
1.0 ⋅ ⋅ -2.0
⋅ 3.14 ⋅ 0.4
5.1 ⋅ ⋅ 0.06
@show A.colptr
@show A.rowval
A.nzval
A.colptr = [1, 3, 4, 4, 7]
A.rowval = [1, 3, 2, 1, 2, 3]
6-element Vector{Float64}:
1.0
5.1
3.14
-2.0
0.4
0.06
CSC (or, more commonly outside Matlab/Julia, row-based CSR) are good for matrix operations (multiplication, solve), but sometimes inconvenient to assemble.
Matrix assembly using COO format¶
A
3×4 SparseMatrixCSC{Float64, Int64} with 6 stored entries:
1.0 ⋅ ⋅ -2.0
⋅ 3.14 ⋅ 0.4
5.1 ⋅ ⋅ 0.06
sparse([1, 1, 2, 2, 3, 3, 1],
[1, 4, 2, 4, 1, 4, 1],
[1, -2, 3.14, .4, 5.1, .06, 10])
3×4 SparseMatrixCSC{Float64, Int64} with 6 stored entries:
11.0 ⋅ ⋅ -2.0
⋅ 3.14 ⋅ 0.4
5.1 ⋅ ⋅ 0.06
Upwind advection-diffusion solver using COO¶
function advdiff_sparse(n, kappa, wind, forcing)
x = LinRange(-1, 1, n)
xstag = (x[1:end-1] + x[2:end]) / 2
rhs = forcing.(x)
kappa_stag = kappa.(xstag)
rows = [1, n]
cols = [1, n]
vals = [1., 1.] # diagonals entries (float)
rhs[[1,n]] .= 0 # boundary condition
for i in 2:n-1
flux_L = -kappa_stag[i-1] * fdstencil(x[i-1:i], xstag[i-1], 1) +
wind * (wind > 0 ? [1 0] : [0 1])
flux_R = -kappa_stag[i] * fdstencil(x[i:i+1], xstag[i], 1) +
wind * (wind > 0 ? [1 0] : [0 1])
weights = fdstencil(xstag[i-1:i], x[i], 1)
append!(rows, [i,i,i])
append!(cols, i-1:i+1)
append!(vals, weights[1] * [flux_L..., 0] + weights[2] * [0, flux_R...])
end
L = sparse(rows, cols, vals)
x, L, rhs
end
advdiff_sparse (generic function with 1 method)
Assembly cost¶
n = 400; h = 2/n
kappa = 1
wind = 100
x, L, rhs = advdiff_sparse(n, x -> kappa, wind, one)
@show minimum(diff(x))
plot(x, L \ rhs, legend=:none, title="Pe_h $(wind*h/kappa)")
minimum(diff(x)) = 0.005012531328320691
n = 10000
@time advdiff_upwind(n, one, 1, one);
@time advdiff_sparse(n, one, 1, one);
0.543603 seconds (708.34 k allocations: 803.497 MiB, 19.04% gc time)
0.195921 seconds (698.92 k allocations: 44.198 MiB, 35.39% gc time)
A = spzeros(5, 5)
A[1,1] = 3
A
5×5 SparseMatrixCSC{Float64, Int64} with 1 stored entry:
3.0 ⋅ ⋅ ⋅ ⋅
⋅ ⋅ ⋅ ⋅ ⋅
⋅ ⋅ ⋅ ⋅ ⋅
⋅ ⋅ ⋅ ⋅ ⋅
⋅ ⋅ ⋅ ⋅ ⋅